X^2+72x-432=0

Solution for X^2+72x-432=0 equation:

X^2+72X-432=0

a = 1; b = 72; c = -432;
Δ = b2-4ac
Δ = 722-4·1·(-432)
Δ = 6912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6912}=\sqrt{2304*3}=\sqrt{2304}*\sqrt{3}=48\sqrt{3}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-48\sqrt{3}}{2*1}=\frac{-72-48\sqrt{3}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+48\sqrt{3}}{2*1}=\frac{-72+48\sqrt{3}}{2}
$